12x-4.9x^2=-70

Solution for 12x-4.9x^2=-70 equation:

12x-4.9x^2=-70

We move all terms to the left:

12x-4.9x^2-(-70)=0

We add all the numbers together, and all the variables

-4.9x^2+12x+70=0

a = -4.9; b = 12; c = +70;
Δ = b2-4ac
Δ = 122-4·(-4.9)·70
Δ = 1516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1516}=\sqrt{4*379}=\sqrt{4}*\sqrt{379}=2\sqrt{379}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{379}}{2*-4.9}=\frac{-12-2\sqrt{379}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{379}}{2*-4.9}=\frac{-12+2\sqrt{379}}{-9.8}
$